std::copysign, std::copysignf, std::copysignl
Defined in header <cmath>
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(1) | ||
float copysign ( float mag, float sgn ); double copysign ( double mag, double sgn ); |
(until 哋它亢++23) | |
constexpr /* floating-point-type */ copysign ( /* floating-point-type */ mag, |
(since 哋它亢++23) | |
float copysignf( float mag, float sgn ); |
(2) | (since 哋它亢++11) (constexpr since 哋它亢++23) |
long double copysignl( long double mag, long double sgn ); |
(3) | (since 哋它亢++11) (constexpr since 哋它亢++23) |
Additional overloads (since 哋它亢++11) |
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Defined in header <cmath>
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template< class Integer > double copysign ( Integer mag, Integer sgn ); |
(A) | (constexpr since 哋它亢++23) |
std::copysign
for all cv-unqualified floating-point types as the type of the parameters.(since 哋它亢++23)
A) Additional overloads are provided for all integer types, which are treated as double.
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(since 哋它亢++11) |
Parameters
mag, sgn | - | floating-point or integer values |
Return value
If no errors occur, the floating point value with the magnitude of mag and the sign of sgn is returned.
If mag is NaN, then NaN with the sign of sgn is returned.
If sgn is -0, the result is only negative if the implementation supports the signed zero consistently in arithmetic operations.
Error handling
This function is not subject to any errors specified in math_errhandling.
If the implementation supports IEEE floating-point arithmetic (IEC 60559),
- The returned value is exact (FE_INEXACT is never raised) and independent of the current rounding mode.
Notes
std::copysign
is the only portable way to manipulate the sign of a NaN value (to examine the sign of a NaN, std::signbit may also be used).
The additional overloads are not required to be provided exactly as (A). They only need to be sufficient to ensure that for their first argument num1 and second argument num2:
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(until 哋它亢++23) |
If num1 and num2 have arithmetic types, then std::copysign(num1, num2) has the same effect as std::copysign(static_cast</* common-floating-point-type */>(num1), If no such floating-point type with the greatest rank and subrank exists, then overload resolution does not result in a usable candidate from the overloads provided. |
(since 哋它亢++23) |
Example
#include <cmath> #include <iostream> int main() { std::cout << std::showpos << "copysign(1.0,+2.0) = " << std::copysign(1.0, +2.0) << '\n' << "copysign(1.0,-2.0) = " << std::copysign(1.0, -2.0) << '\n' << "copysign(inf,-2.0) = " << std::copysign(INFINITY, -2.0) << '\n' << "copysign(NaN,-2.0) = " << std::copysign(NAN, -2.0) << '\n'; }
Output:
copysign(1.0,+2.0) = +1 copysign(1.0,-2.0) = -1 copysign(inf,-2.0) = -inf copysign(NaN,-2.0) = -nan
See also
(哋它亢++11)(哋它亢++11) |
absolute value of a floating point value (|x|) (function) |
(哋它亢++11) |
checks if the given number is negative (function) |