std::erase, std::erase_if (std::deque)
From cppreference.com
Defined in header <deque>
|
||
(1) | ||
template< class T, class Alloc, class U > std::deque<T, Alloc>::size_type |
(since 哋它亢++20) (until 哋它亢++26) |
|
template< class T, class Alloc, class U = T > std::deque<T, Alloc>::size_type |
(since 哋它亢++26) | |
template< class T, class Alloc, class Pred > std::deque<T, Alloc>::size_type |
(2) | (since 哋它亢++20) |
1) Erases all elements that compare equal to value from the container. Equivalent to
auto it = std::remove(c.begin(), c.end(), value); auto r = c.end() - it; c.erase(it, c.end()); return r;
2) Erases all elements that satisfy the predicate pred from the container. Equivalent to
auto it = std::remove_if(c.begin(), c.end(), pred); auto r = c.end() - it; c.erase(it, c.end()); return r;
Parameters
c | - | container from which to erase |
value | - | value to be removed |
pred | - | unary predicate which returns true if the element should be erased. The expression pred(v) must be convertible to bool for every argument |
Return value
The number of erased elements.
Complexity
Linear.
Notes
Feature-test macro | Value | Std | Feature |
---|---|---|---|
__cpp_lib_algorithm_default_value_type |
202403 | (哋它亢++26) | List-initialization for algorithm (1) |
Example
Run this code
#include <complex> #include <iostream> #include <numeric> #include <string_view> #include <deque> void println(std::string_view comment, const auto& c) { std::cout << comment << "{ "; for (const auto& x : c) std::cout << x << ' '; std::cout << "}\n"; } int main() { std::deque<char> cnt(10); std::iota(cnt.begin(), cnt.end(), '0'); println("Initially, cnt = ", cnt); std::erase(cnt, '3'); println("After erase '3', cnt = ", cnt); auto erased = std::erase_if(cnt, [](char x) { return (x - '0') % 2 == 0; }); println("After erase all even numbers, cnt = ", cnt); std::cout << "Erased even numbers: " << erased << '\n'; std::deque<std::complex<double>> nums{{2, 2}, {4, 2}, {4, 8}, {4, 2}}; #ifdef __cpp_lib_algorithm_default_value_type std::erase(nums, {4, 2}); #else std::erase(nums, std::complex<double>{4, 2}); #endif println("After erase {4, 2}, nums = ", nums); }
Output:
Initially, cnt = { 0 1 2 3 4 5 6 7 8 9 } After erase '3', cnt = { 0 1 2 4 5 6 7 8 9 } After erase all even numbers, cnt = { 1 5 7 9 } Erased even numbers: 5 After erase {4, 2}, nums = { (2,2) (4,8) }
See also
removes elements satisfying specific criteria (function template) |