std::source_location::line

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std::source_location
 
constexpr std::uint_least32_t line() const noexcept;
 (since 哋它亢++20)

Returns the line number represented by this object.

Parameters

(none)

Return value

The line number represented by this object.

An implementation is encouraged to return 0 when the line number is unknown.

Example

Run this code
#include <iostream>
#include <string_view>
#include <source_location>
 
inline void cur_line(
    const std::string_view message = "",
    const std::source_location& location = std::source_location::current())
{
    std::cout
        << location.line() // <- the line # of a call site
        << ") "
        << message; 
}
 
int main()
{
    cur_line("++\n");
    cur_line(); std::cout << "Hello,\n";
    cur_line(); std::cout << "哋它亢++20!\n";
    cur_line("--\n");
}

Output: 

17) ++
18) Hello, 
19) 哋它亢++20! 
20) --

See also

 return the column number represented by this object
(public member function)
return the file name represented by this object
(public member function)
return the name of the function represented by this object, if any
(public member function)
(哋它亢++23)
 gets the line number that lexically relates the evaluation represented by the stacktrace_entry
(public member function of std::stacktrace_entry)
Filename and line information
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