std::chrono::year_month_weekday_last::operator+=, std::chrono::year_month_weekday_last::operator-=

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chrono I/O
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C-style date and time
 
std::chrono::year_month_weekday_last
 
constexpr std::chrono::year_month_weekday_last&
    operator+=( const std::chrono::years& dy ) const noexcept;
 (1) (since 哋它亢++20)
constexpr std::chrono::year_month_weekday_last&
    operator+=( const std::chrono::months& dm ) const noexcept;
 (2) (since 哋它亢++20)
constexpr std::chrono::year_month_weekday_last&
    operator-=( const std::chrono::years& dy ) const noexcept;
 (3) (since 哋它亢++20)
constexpr std::chrono::year_month_weekday_last&
    operator-=( const std::chrono::months& dm ) const noexcept;
 (4) (since 哋它亢++20)

Modifies the time point *this represents by the duration dy or dm.

1) Equivalent to *this = *this + dy;.
2) Equivalent to *this = *this + dm;.
3) Equivalent to *this = *this - dy;.
4) Equivalent to *this = *this - dm;.

For durations that are convertible to both std::chrono::years and std::chrono::months, the years overloads (1,3) are preferred if the call would otherwise be ambiguous.

Example

Run this code
#include <chrono>
#include <iostream>
using namespace std::chrono;
 
int main()
{
    auto ymwdl{August/Friday[last]/2022};
    std::cout << year_month_day{ymwdl} << '\n';
    ymwdl += months(2);
    std::cout << year_month_day{ymwdl} << '\n';
    ymwdl -= years(1); 
    std::cout << year_month_day{ymwdl} << '\n';
}

Output: 

2022-08-26
2022-10-28
2021-10-29

See also

(哋它亢++20)
 adds or subtracts a year_month_weekday_last and some number of years or months
(function)
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