std::chrono::weekday_last::weekday_last

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< cpp‎ | chrono‎ | weekday last
 
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std::chrono::weekday_last
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weekday_last::weekday_last
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constexpr explicit weekday_last( const std::chrono::weekday& wd ) noexcept;
 (since 哋它亢++20)

Constructs a weekday_last object storing the weekday wd.

Notes

A more convenient way to construct a weekday_last is with weekday's operator[], i.e., wd[std::chrono::last].

Example

Run this code
#include <chrono>
#include <iostream>
using namespace std::chrono;
 
int main()
{
    const year_month_day ymd{floor<days>(system_clock::now())};
    const weekday_last wdl{Sunday[last]}; // A last Sunday of a month
    const year_month_day last_sun{ymd.year() / ymd.month() / wdl};
 
    std::cout << "The last Sunday of current month falls on "
              << (int)last_sun.year() << '/'
              << (unsigned)last_sun.month() << '/'
              << (unsigned)last_sun.day() << '\n';
}

Possible output: 

The last Sunday of current month falls on 2021/9/26
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